36m^2-104m-68=0

Solution for 36m^2-104m-68=0 equation:

36m^2-104m-68=0

a = 36; b = -104; c = -68;
Δ = b2-4ac
Δ = -1042-4·36·(-68)
Δ = 20608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20608}=\sqrt{64*322}=\sqrt{64}*\sqrt{322}=8\sqrt{322}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-8\sqrt{322}}{2*36}=\frac{104-8\sqrt{322}}{72}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+8\sqrt{322}}{2*36}=\frac{104+8\sqrt{322}}{72}
$